Light of wavelength 630 nm falls on two slits and produces an interference pattern in which the third-order bright red fringe is 35 mm from the central fringe on a screen 2.8 m away. Part A What is the separation of the two slits?

The separation of the two slits is = 1.5 × m

Explanation:

Wave length = 630 nm = 0.63 mm

x = 35 mm

l = 2.8 m

Order of fringes (m) = 3

We know that the separation of the two slits is given by

Put all the values in above formula we get

d = 1.5 × m

Therefore the separation of the two slits is = 1.5 × m

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