Three point charges lie in a straight line along the y-axis. A charge of q1 = -10.00 µC is at y = 6.40 m, and a charge of q2 = -7.70 µC is at y = -3.60 m. The net electric force on the third point charge is zero. Where is this charge located?

y coordinate where field is zero is  1.1 m

Explanation:

given data

charge q1 = -10.00 µC

y = 6.40 m,

charge q2 = -7.70 µC

y = -3.60 m

solution

we know that here Electric field E that is express as

Electric field E =   ..............................1

and

Distance between charges will be

Distance between charges = 6.40 -  (-3.60) = 10 m

so here neutral point P is at  distance d from q1

so it is  distance (10 - d) from q2.  

so here

Field from q1 at P =

and

Field from q2 at P =

so here field is  in opposite directions and the resultant field = 0

so

d =  5.326242 m

so y coordinate where field is zero is 6.40 - 5.32 = 1.1 m

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

i think its c if i'm wrong