A flat, square coil of 18 turns that has sides of length 14.0 cm is rotating in a magnetic field of strength 0.040 T. If the maximum emf produced in the coil is 36.0 mV, what is the angular velocity of the coil (in rad/s)? (Enter the magnitude.)

The angular velocity of the coil is .

Explanation:

The expression  for the maximum emf is as follows;

                                                   ......... (1)

Here, is the emf, {tex]\omega[/tex] is the angular velocity, N is the number of turns, B is the magnetic field and A is the area.

Calculate the area of the square coil.

Convert side of the length form cm to m.

s= 0.14 m

Here, A is the area and s is the length of the side of the square.

Put s= 0.14 m.

Convert maximum emf from mV to V.

Calculate the angular velocity of the coil by rearranging the equation (1).

Put , , B= 0.040 T and N= 18 turns.

Therefore, the angular velocity of the coil is .

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answer; equivalent to a one(1) horsepower motor;