Physics, 30.03.2020 21:57, humpty21

Two loops of wire are arranged so that a changing current in one, the primary, will induce a current in the other, the secondary. The secondary loop has twice as many turns as the primary loop. As long as the current in the primary is steady at 3.0 A, the current in the secondary will be:

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answered: gabe7774

the current in the secondary loop will be = 1.5A

Explanation:

In an ideal transformer, conservation of energy requires that power out to equal power in Thus, Ip x Vp = Vs x Is, or Ip = Vs x Is / Vp.

Since Vs = Ns x Vp / Np, Ip can be rewritten as Ip = ( Ns x Vp / Np ) x Is / Vp, or equivalently, Ip = Ns x Is / Np, or Ns x Is = Np x Ip

Thus, Np x Ip = Ns x Is

Where;

Ip = current in primary loop = 3A

Is = current in secondary loop

Np = number of turns in primary loop = n

Ns = number of turns in secondary loop = 3n

Now, we are told that the current in the primary loop is 3 A. So, Ip = 3A

We are also told that the secondary loop has twice as many turns as the primary loop. Thus, let's call the number of of turns in primary loop "y" Thus, Np = y and Ns = 2y

Let's plug these values into;

Np x Ip = Ns x Is

y x 3 = 2y x Is

Divide both sides by 2y;

3y/2y = 2y(Is)/2y

2y will cancel out, on the right and y will cancel out on the left,

so Is = 3/2A = 1.5A

answered: Guest

number of electrons for neutral cl

answered: Guest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s