A 12n net force acts on a 4-kg jug of water. What is the resulting acceleration of the jug?

3m/s^2

Explanation:

Net force = 12N

Mass of jug = 4kg

Acceleration of the jug = ?

Recall that force is the product of the mass of an object by the acceleration by which it moves.

i.e Force = Mass x Acceleration

12N = 4kg x Acceleration

Acceleration = 12N/4kg

Acceleration = 3m/s^2

Thus, the resulting acceleration of the jug is 3m/s^2

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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