A total electric charge of 3.50 nC is distributed uniformly over the surface of a metal sphere with a radius of 24.0 cm. If the potential is zero at a point at infinity, find the value of the potential at the following distances from the center of the sphere: (a) 48.0 cm; (b) 24.0 cm; (c) 12.0 cm

a, V = 65.6V

b. V = 131.0V

C. V = 131.0V

Explanation:

Given

Total electric charge distributed  uniform at surface of metal sphere where radius is R = 24cm

R = 24cm = 0.024m

we have to find potential at different distance

a. r = 48cm = 0.048m

b. r = 24cm = 0.024m

c. r = 12cm = 0.012m

a. solution

Here the distance r is grater then R,we can get the potential outside of sphere

now we plug the value q and r in potential v

=65.6V

b.solution

Here distane r is the same from radius R, so we can get potential inside sphere

Now we plug the value of R and q

3.solution

Inside sphere electric feild is zero.so potential is the same every point inside sphere and equal potential on the surface

hypothesising or postulating

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s