A single conservative force acts on a 4.50-kg particle within a system due to its interaction with the rest of the system. The equation Fx = 2x + 4 describes the force, whereFx is in newtons and x is in meters. As the particle moves along the x axis from x = 0.90 m to x = 5.15 m, calculate the following.
(a) the work done by this force on the particle? (J)
(b) the change in the potential energy of the system? (J)
(c) the kinetic energy the particle has at x = 5.15 m if its speed is 3.00 m/s at x = 0.90 m? (J)
Answers: 1
Physics, 22.06.2019 10:50, afonseca73
Asheet of steel 1.5 mm thick has nitrogen atmospheres on both sides at 1200oc and is permitted to achieve a steady-state diffusion condition. the diffusion coefficient for nitrogen in steel at this temperature is 6 x 10- 11 m2 /s, and the diffusion flux is found to be 1.2 x 10-7 kg/m2 -s. also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 4 kg/m3 . how far into the sheet from this high-pressure side will the concentration be 2.0 kg/m3 ? assume a linear concentration profile.
Answers: 3
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