A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.

At this time, the rocket runs out of fuel and turns off, and the car deploys a parachute to slow down, and the parachute performs 36,733 J of work on the car.

What is the final speed of the car after this work is performed?

9.43 m/s

Explanation:

From law of conservation of energy, the initial magnitude and final magnitude of work is same. The magnitude of work done by car finally is given by getting the differences between the initial kinetic energy and work done by parachute on car hence 66120-36733=29387 J

Kinetic energy,

Making v the subject of the formula then

where m is the mass and v is the velocity of the car.

Substituting 29387 J for Ke and 661 Kg for mass then

c

explanation:

i believe the answer is c and this is only worth 10 points you might wanna change it

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.