Kid A has jumped off the sled! (RIP)

Two kids are left riding on a snow sled traveling horizontally without friction at 11.7 m/s. The masses of kid B, and C are 36.7 kg, and 45.2 kg, respectively.

What is the new velocity of the sled if Kid B jumps off backwards at v = -31.1 m/s?

46.45 m/s

Explanation:

Total momentum before jump = Total momentum after jump

11.7 * ( 36.7 + 45.2 ) = ( 36.7 * (-31.1) ) + ( 45.2 * v )

v*45.2 - 1141.37 = 958.23

v = 2099.6/45.2 = 46.45

b.transmitters send radio waves, and receivers capture radio waves.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2