A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

0.027 J

Explanation:

The formula of the potential energy in electrostatic (U) is

The values given in the question are

Charge : q =

Electric Field strength : E =

Distance : d  is 0.030 m

Insert in the formula , will give us

Further solving it

Which is the required answer.

Thanks

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