A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s, and its initial position was 0 m, what is its final position?
-385m
32m
385m
242.2m
-242.2m

The final position of the car is 385 m.

Explanation:

We know the formula :

                                   s =  

where,

                                     s = distance

                                     u = initial velocity = 5.1 m/s

                                      t = time taken = 14 sec

                                     a = acceleration = 3.2 m/

Solving:

                         s = 5.1* 14 + * 3.2 *

                      ∴ s = 385 m

Hence the final position of the car is 385 m.

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

d) physical means can be used to separate the components of air.