En una taza de cerámica de 0.5 kilogramos se sirve café caliente con un calor específico de 4186 Julios/ ( kilogramos grados Celsius). ¿Cuanto calor absorbe la taza si la temperatura se eleva de 20 a 80 Celsius?

Heat required to raise the temperature of coffee is given as

Explanation:

As we know that the mass of the coffee is given as

m = 0.5 kg

specific heat capacity is given as

s = 4186 J/kg C

Now we know that the heat required to raise the temperature of coffee is given as

now we have

a and b sometimes have a positive value

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