What happens when one side of the tug-of-war rope has a large net force than the other?
What happens when both sides of the tug-of-war rope are equal in force? What is the net force in this scenario?
What happens to the speed when the two small people are placed on one side and the two taller people are placed on the other side? What about when it is one small person on one side versus all four people on the other side?
Which objects did you choose to put onto the skateboard?
Complete the simulation for three different trials. Complete chart below, using the data for your simulation from each trial.
Trial number Mass on Skateboard Applied Force by Person Speed When Let Go
1
2
3
Based on your data table, is the relationship between speed and force direct or indirect? Explain your answer.
Based on your data table, is the relationship between mass and speed (with constant force) direct or indirect? Explain your answer.
How does time of force applied impact the speed of the skateboard?
Complete the first trial three trials from question 5, but now change the friction in each one.
Trial number Mass on Skateboard Applied Force by Person Friction Speed When Let Go
1 Same as Trial #1, Question 5 Same as Trial #1, Question 5
2 Same as Trial #1, Question 5 Same as Trial #1, Question 5
3 Same as Trial #1, Question 5 Same as Trial #1, Question 5
Based on your data, is the relationship between friction and speed direct (both go up), or indirect (one decreases and the other increases)? Explain how your data support this answer.
When the friction increases too much, does the object stay still or move in the opposite direction?
What is the relationship between force and acceleration?

1.When one side of the tug-of-war rope has a larger net force than the other side then the basket in the middle will be pulled to whichever side has a larger net force. As the sum of forces increases, the speed of the cart goes faster throughout the tug of war.

2.When both sides of the tug-of-war rope are made equal in force than the rope does not move at all. There is a mass of 350 N on both sides of the cart. The net force in this scenario is 0 because there is no difference in mass.

3.With the first example, the speed odometer gets up to right next to the “S” in speed. With one small person verse all four on the other side, the speed odometer moves all the way past halfway to the d in Speed.

4.The objects selected will vary.

5.The chart will look different depending on the ratio of weights that you put on the skateboard. The answers provide what a chart might look like.

Trial numberMass on SkateboardApplied Force by PersonSpeed When Let Go

1  330 kg  200 N  3.3 m/s

2  100 kg   200 N  9.2 m/s

3  340 kg  200 N  1.1 m/s

6.The relationship between speed and force is direct because regardless of the mass on the skateboard and the force involved, they continue to increase. The greater the force applied to the skateboard when it is released, the higher the speed of the skateboard.

7.The relationship between mass and speed (with constant force) is indirect. The higher the mass that needs to be pushed, the lower the starting speed is of the skateboard.

8.The longer the force is applied to the skateboard, the higher the speed of the skateboard will be. Even with the heaviest possible skateboard, the speed will max out after a certain period of time. The time needed to do this is shorter when the mass is lighter, indicating a direct relationship between the variables.

9.Your chart may look different based on the results from your first trial completed in question 5.

Trial numberMass on SkateboardApplied Force by PersonFrictionSpeed When Let Go

1Same as Trial #1, Question 5Same as Trial #1, Question 5  None  2.7 m/s

2Same as Trial #1, Question 5  Same as Trial #1, Question 5Medium  0.0 m/s  

3  Same as Trial #1, Question 5Same as Trial #1, Question 5Lots  0.0 m/s  

10.The relationship between speed and friction is indirect because as the friction increases the speed decreases.

11.The object stays still when there is too much friction applied to the equation with the mass and applied force.

12.The relationship between force and acceleration is directly proportional. Whatever the force is that is applied to the object, the acceleration of that object increased by the same factor.

Explanation:

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