An elevator moves downwards at a constant speed. When drawing the free body diagram for this motion:

A) there is no upwards tension force, only a gravity force.
B) the upwards tension force should should be drawn the same length as the downwards gravity force.
C)The upwards tension force should be drawn longer than the downwards gravity force.
D) The upwards tension force should be drawn shorter than the downwards gravity force.

a, c, d, e are all applying about success strategies.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s