Physics, 25.03.2020 17:59, oscarurtiz89
If the potential due to a point charge is 5.05 β 102 V at a distance of 15.7 m, what are the sign and magnitude of the charge? (Enter your answer in C.)
Answers: 2
Physics, 21.06.2019 14:30, clairajogriggsk
Define the meaning of the unalienable rights of life liberty and persuit of happiness
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Physics, 21.06.2019 18:10, eweqwoewoji
Scientists use laser range-finding to measure the distance to the moon with great accuracy. a brief laser pulse is fired at the moon, then the time interval is measured until the "echo" is seen by a telescope. a laser beam spreads out as it travels because it diffracts through a circular exit as it leaves the laser. in order for the reflected light to be bright enough to detect, the laser spot on the moon must be no more than 1.0 km in diameter. staying within this diameter is accomplished by using a special large-diameter laser. part a if Ξ» = 540nm , what is the minimum diameter of the circular opening from which the laser beam emerges? the earth-moon distance is 384,000 km. express your answer to two significant figures and include the appropriate units.
Answers: 1
Physics, 21.06.2019 21:30, Nibiskadhungana
According to social exchange theory, altruistic behaviors benefit the individual who performs them. t/f
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Physics, 22.06.2019 19:00, hairyears3394
Review multiple-concept example 7 in this chapter as an aid in solving this problem. in a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so that the ball in her hand moves in a circle. in one instance, the radius of the circle is 0.626 m. at one point on this circle, the ball has an angular acceleration of 66.1 rad/s2 and an angular speed of 12.6 rad/s. (a) find the magnitude of the total acceleration (centripetal plus tangential) of the ball. (b) determine the angle of the total acceleration relative to the radial direction.
Answers: 3
If the potential due to a point charge is 5.05 β 102 V at a distance of 15.7 m, what are the sign an...
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