In a simple electric circuit, Ohm's law states that V=IRV=IR, where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.01 volts per second and, as the resistor heats up, the resistance is increasing at 0.04 ohms per second. When the resistance is 300 ohms and the current is 0.01 amperes, at what rate is the current changing?

To solve this problem, apply the concepts given from Ohm's Law. From there we will obtain the derivative of the function with respect to time and with the previously given values we will proceed to find the change in current as a function of the derivative

Here

I = Current

V = Voltage

R = Resistance

Taking the derivative we will have,

Our values are given as,

Replacing we will have that

Rearranging to find the current through the time,

Therefore the change of the current is -0.000026A per second

explanation:

could i give you a exaplo that could you?

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.