Two speakers are driven by a common oscillator at 840 Hz and face each other at a distance of 1.24 m. Locate the points along a line joining the two speakers where relative minima of pressure amplitude would be expected. (Use v = 343 m/s. Choose one speaker as the origin and give your answers in order of increasing distance from this speaker. Enter 'none' in all unused answer boxes.)

1)

2)  

3)  

4)  

Explanation:

Let's recall that two antinodes are required for a complete wavelength in standing waves which are produced by the facing speakers.

The equation for the spacing between two nodes of a stationaty wave is:

(1)

Now, we know that velocity of a sound wave is:

(2)

We can solve the equation 1 for λ and put it on equation 2

The antinode is formed in the half distance between both speakers, so:

x = 1.24/2 = 0.62 m

The location of the node will be:

Therefore the nodes will be:

1)

2)  

3)  

4)  

I hope it helps you!

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests