Ask Your Teacher Two wires, each of length 1.5 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave whose frequency is 456 Hz. However, the same frequency of 456 Hz is the third harmonic on wire B. Find the speed at which the individual waves travel on each wire.

Explanation:

Given:

Length, L = 1.5 m

Frequency, f = 456 Hz

Velocity, v = frequency, f × wavelength, λ

At the second harmonic,

f = 2 × (v/2L)

v = 456 × 1.5

= 684 m/s

At the third harmonic,

f = 3 × (v/2L)

Where,

v = velocity

v = 2/3 × 456 × 1.5

= 456 m/s

i think it's 35 meters

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.