Two skaters, one with mass 75 kg and the other with mass 60 kg, stand on an ice rink holding a pole of length 14 m and negligible mass. Starting from the ends of the pole, the skaters pull themselves along the pole until they meet. How far does the 60 kg skater move

The 60 kg skater move 7.8 m

Explanation:

given information:

first skater's mass, m₁ = 75 kg

second skater's mass, m₂ = 60 kg

pole length, x = 14 m

to calculate how far the the second skater moved, we can use the following equation:

= Σ

where

M = ∑

   = m₁ + m₂

   = 75 + 60

   = 135 kg

= Σ

= (m₁x₁ + m₂x₂), = 0 since both skater meet

now let assume the the second skater moved x₂ = a m, so the first skater moved x₁ = 14 - a

so,

= (m₁x₁ + m₂x₂)

0 = [(75(14-a) + 60a)]

0 = (1050 - 75a + 60(-a))

0 = (1050 - 135a)

135a = 1050

a = 1050/135

  = 7.8 m

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

it breaks and dirupture other materials and other sencews from the bottom