The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 mA. What is the electric field in the wire?

0.0360531138247 V/m

Explanation:

= Resistivity of gold = (General value)

I = Current = 940 mA

d = Diameter = 0.9 mm

A = Area =

E = Electric field

Resistivity is given by

The  electric field in the wire is 0.0360531138247 V/m

Explanation:

Current in the wire, i = 940 mA = 0.94 A

Length of the wire, l = 14 cm = 0.14 m

diameter of wire = 0.9 mm

radius of wire, r = 0.45 mm = 0.45 x 10^-3 m

resistivity of gold, ρ = 2.44 x 10^-8 ohm metre

Let R is the resistance of the wire.

R = 5.37 x 10^-3 ohm

By the Ohm's law

V = i x R

V = 0.94 x 5.37 x 10^-3

V = 5.05 x 10^-3 V

E = V / l = (5.05 x 10^-3) / 0.14 = 0.036 V/m

higher potential

explanation:

because it is in a high speed so it must move into a of high potential