Physics, 23.03.2020 21:42, kalebstone8357
A 9.29 kg particle with velocity is at x = 7.86 m, y = 9.84 m. It is pulled by a 9.78 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?
Answers: 1
where r= x+y 
![l=9.29[(7.86i+9.84j)(6i-7j)]\\l=9.29*[-55.02ij+59.04]\\l=1059.6k kgm^{2} /s](/tpl/images/0559/5739/36bfa.png)
![r=r*F\\r=(7.86i+9.84j)m*(-9.78)N\\r=9.29kg*[-96.24ij]Nm\\r=(+96.24k)Nm](/tpl/images/0559/5739/a2c7b.png)
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A 9.29 kg particle with velocity is at x = 7.86 m, y = 9.84 m. It is pulled by a 9.78 N force in the...
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