Physics, 08.10.2019 14:30, buciuceanu8740

Acombined circuit has two resistors in parallel (34.0 ohms and 41.0 ohms) and another in series (15.0 ohms). if the power source is 9.0 volts, what will the current be? . a.. 0.054 amps. b.. 33.6 amps. c.. 0.27 amps. d.. 0.48 amps. e.. 0.60 amps.

Answers: 1

Show answers

Answers

If the power source is 9.0 volts, the current will be 0.27 amps. The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you, and if you would like, feel free to ask another question.

answered: Savageman9509

Answer : Current, I = 0.27 amps

Explanation :

Given that,

Two resistors R₁ = 34.0 ohms and R₂ = 41.0 ohms in parallel and another resistor R₃ = 15.0 ohms in series.

The voltage across them is 9 volts.

Taking the equivalent of R₁ and R₂ :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\dfrac{1}{R_{eq}}=\dfrac{1}{34}+\dfrac{1}{41}$

$R_{eq}=18.58\ \Omega$

Now, Taking series combination of $R_{eq}$ and R₃

So, $R'_{f}=33.58\ \Omega$

Using Ohm/s law :

V=IR

$I=\dfrac{V}{R}$

$I=\dfrac{9\ V}{33.58\ \Omega}$

I = 0.268 A

I = 0.27 amps

So, the correct option is (C) " 0.27 amps "

answered: Guest

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6 $\frac{m}{s^{2} }$

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

answered: Guest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Other questions on the subject: Physics

Physics, 21.06.2019 21:50, jferdi2005

When applying kirchhoff's rules, one of the essential steps is to mark each resistor with plus and minus signs to label how the electric potential changes from one end of the resistor to the other. the circuit in the drawing contains four resistors, each marked with the associated plus and minus signs. however, one resistor is marked incorrectly. which one is it?

Answers: 1

continue

Physics, 22.06.2019 06:00, ahmedeldyame

Why don't you see your reflection in water with waves or repples

Answers: 1

continue

Physics, 22.06.2019 14:00, meleaallison

Amass attached to a spring is displaced from its equilibrium position by 5cm and released. the system then oscillates in simple harmonic motion with a period of 1s. if that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case? a mass attached to a spring is displaced from its equilibrium position by and released. the system then oscillates in simple harmonic motion with a period of . if that same mass–spring system is displaced from equilibrium by instead, what will its period be in this case? a) 0.5sb) 2sc) 1sd) 1.4s

Answers: 2

continue

Physics, 22.06.2019 17:30, etaylor3421

Frequency of electromagnetic waves that a radio station is assigned is called

Answers: 1

continue

Do you know the correct answer?

Acombined circuit has two resistors in parallel (34.0 ohms and 41.0 ohms) and another in series (15....