A technician at a semiconductor facility is using an oscilloscope to measure the AC voltage across a resistor in a circuit. The technician measures the oscillating voltage to be a sine wave with a peak voltage of 7.75 V . However, the technician must record the RMS voltage on a report. What value should be reported

The value to be reported is 5.48V

Explanation:

The RMS (root mean square) is defined as the value of voltage that will produce the same heating effect, or power dissipation, in circuit, as this AC voltage.

The RMS voltage is also called effective voltage because it is just as effective as DC voltage in providing power to an element.

It is expressed as =

where Vm is the maximum or peak value of the voltage

In calculating the RMS of the voltage , we simply divide the peak voltage by square root of 2 (√2)

=

=

= 5.48 V

did yall get answers for this yet