In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same time interval sunshine coming through the windows delivered 2000 J of energy into the house. The temperature of the house didn't change. What was ?Ethermal of the house, and what was |Q|, the magnitude of the energy transfer between the house and the outside air?

?Ethermal = J

|Q| = J

The thermal energy of the house is

The magnitude of the energy transfer is

Explanation:

From the question we are told that

              The energy content is  

               The energy through sunshine is  

Generally the first law of thermodynamics can be mathematically represented as

Where is the heat transferred

            is the change in internal energy with is = 0J  the temperature of the house did not change

            is the workdone which = 0J This because the volume of the air in the house  did not change

   Therefore  

And this is equivalent to the thermal energy of the house

Therefore

          = 0J

Now the  heat transfer from outside to inside can be mathematically  represented as

Now = 19000 + 2000

This because both the energy of the natural and the sunshine are supplied to the house

And  

            = 0 this is because there are no transfer of heat to the surrounding

   Hence

newton's first law of motion

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂