A counterclockwise current flows in a rectangular loop of wire in a uniform magnetic field. a) What is the direction of the force that acts on each side of the wire rectangle

Explanation:

In a rectangular loop of wire, a counter-clockwise current flows in a uniform magnetic field pointing towards right.

There are four sides of the rectangular loop ab, bc, cd and da. Lets analyze each side.

Force on section ab:

The force is zero since the wire is parallel to magnetic field

Fab = 0

Force on section bc:

Fbc = BIL

Since the current I is moving upwards and magnetic field is to the right then force F points into the screen.

Force on section cd:

The force is zero since the wire is parallel to magnetic field

Fcd = 0

Force on section da:

Fda = -Fbc

Since the current I is moving upwards and magnetic field is to the right then force F points out of the screen.

The net force acting on the rectangular loop is

Fnet = Fab + Fbc + Fcd + Fda = 0

0 + Fbc + 0 + Fda = 0

Fda = -Fbc

the answer would be c

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