Physics, 22.03.2020 04:27, reneewilliams20
Two equal positive charges q_1 = q_2 = 2.0μ∁ are located at x= 0, y=0.30m and x=0, y=-0.30m, respectively. What are the magnitude and direction of the total electric force that q_1 and q_2 exert on the third charge Q = 4.0μ∁ at x = 0.40m, y = 0?
Answers: 1
Physics, 21.06.2019 21:20, mmaglaya1
Which of the following explains why it took so long for the public to accept the negative health effects of smoking? a)people were waiting for counter reasons, and those were presented. b)scientists had not completely finalized their results, which took 30 years. c)cigarettes were cheaply available and media channels were very inefficient. d)cigarette manufacturers were trying hard to bring an alternative into the market
Answers: 3
Physics, 22.06.2019 08:30, fernandoramirez086
Does anyone know how to solve this problem? i really need . i made an attempt but i just cant get it. a metal rod is 25.000 cm long at 25.0 degrees celsius. when heated to 102.0 degrees celsius, it is 25.054 cm long. what is the coefficient of linear expansion for this metal.
Answers: 3
Physics, 22.06.2019 12:30, olsen6932
As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arranged side by side so that they are parallel to each other. when you push the platform, you compress the springs. you do an amount of work of 79.0 j when you compress the springs a distance of 0.230 m from their uncompressed length. (a) what magnitude of force must you apply to hold the platform in this position? (b)how much additional work must you do to move the platform a distance 0.230 m farther? (c) what maximum force must you apply to move the platform a distance 0.230 m farther?
Answers: 1
Physics, 22.06.2019 21:10, alexiaalfaro
The junction rule describes the conservation of which quantity? note that this rule applies only to circuits that are in a steady state.
Answers: 1
Two equal positive charges q_1 = q_2 = 2.0μ∁ are located at x= 0, y=0.30m and x=0, y=-0.30m, respect...
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