A rectangular loop of wire of width 10 cm and length 20 cm has a current of 2.5 A flowing through it. Two sides of the loop are oriented parallel to a uniform magnetic field of strength 0.037 T, the other two sides being perpendicular to the magnetic field. The magnitude of the torque on the loop is .

0.00185 Nm

Explanation:

Parameters given:

Width of loop = 10cm = 0.1m

Length of loop = 20cm = 0.2m

Current, I = 2.5 A

Magnetic field strength, B = 0.037 T

Magnetic torque, τ, is given as:

τ = N * I * A * B * sinθ

Where N = Number of turns (in this case 1)

θ = angle between magnetic field and perpendicular of loop (90°)

A = area of loop = length * width = 0.2 * 0.1 = 0.02 m²

τ = 1 * 2.5 * 0.02 * 0.037 * sin90

τ = 0.00185 Nm

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.