A resistance of 10 , an inductor of 10/377 henries, and a capacitor of 0.1/377 farads are all connected in series to a 60-hertz, 100-volt source. Determine the magnitude of the current.

The magnitude of the current is 10 A.

Explanation:

Given that,

Resistance, R = 10 ohms

Inductance,

Capacitance,

Voltage, V = 100 V

Frequency, f = 60 Hz  

At resonance condition, the resistance of the circuit is equal to its impedance. It is given by :

Let I is the current. It can be calculated using Ohm's law as :

V = I Z

So, the magnitude of the current is 10 A. Hence, this is the required solution.

v=ir = 3x15 =45 v

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.