A current of 19.5 mA is maintained in a single circular loop with a circumference of 2.30 m. A magnetic field of 0.710 T is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop?

0.0058 Nm

Explanation:

Parameters given:

Number of turns, N = 1

Current, I = 19.5 mA = 0.0195 A

Circumference = 2.3 m

Magnetic field, B = 0.710 T

Angle, θ = 90°

Magnetic torque is given as:

τ = N * I * A * B * sinθ

Where A is area

Circumference is given as:

C = 2 * pi * r

=> 2.3 = 2 * pi * r

=> r = 2.3/(2 * 3.142)

r = 0.366 m

Area, A can now be found:

A = pi * r² = 3.142 * 0.366²

A = 0.42 m²

Therefore, torque is:

τ = 1 * 0.0195 * 0.42 * 0.71 * sin90

τ = 0.0058 Nm

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

increases it