Assume the bike has a mass of 20 kg and is moving down at -9 m/s when it is thrown off the balcony. When the bike hits the ground it still has a mass of 20 kg but the bike is not longer moving. What is the change in momentum of the bike?

180 kgm/s

Explanation:

From Newton's second law of motion,

ΔM = m(v-u) Equation 1

Where ΔM = change in momentum of the bike, m = mass of the bike, v = final velocity of the bike, u = initial velocity of the bike.

Given: m = 20 kg, u = -9 m/s, v = 0 m/s ( the bike is no longer moving)

Substitute into equation 1

ΔM = 20[0-(-9)]

ΔM = 20(9)

ΔM = 180 kgm/s.

Hence the change in momentum of the bike = 180 kgm/s

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