A 12.0 μF capacitor is connected to a power supply that keeps a constant potential difference of 26.0 V across the plates. A piece of material having a dielectric constant of 3.80 is placed between the plates, completely filling the space between them.
(a) How much energy is stored in the capacitor before the dielectric is inserted?
(b) How much energy is stored in the capacitor after the dielectric is inserted?
(c) By how much did the energy change during the insertion? Did it increase or1 decrease?
(d) Explain why inserting the dielectric (or equivalently exchanging air with the material) causes a change in the stored energy of the capacitor.

0.004056 J

0.0154128 J

Increase

Explanation:

C = Capacitance  = 12 μF

V = Potential difference = 26 V

K = Dielectric constant = 3.8

New capacitance is

Energy in the capacitor

Before insertion energy 0.004056 J

After insertion

After insertion energy 0.0154128 J

Change in energy

There is an increase in energy.

The dielectric constant of air is about 1.00059 here the dielectric constant is 3.8 which is higher so the energy increases.

sleep paralysis is a parasomnia, events associated with sleep.

sleep paralysis happens when you are in the middle of waking up or falling asleep. it is the feeling of being conscious but unable to move. it definitely involves hallucinations.

i had a friend that had sleep paralysis and he told me a story one time where he was laying in bed and he couldn't move his body no matter how hard he tried and there was someone standing in the corner of his room coming towards him. he couldn't move and you can't "wake up" because you are already conscious. sometimes sleep paralysis can be triggered by frequent waking up during the night based off of multiple trips to the bathroom, or if you had ever been abused, sleep paralysis can start happening from things like that.

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