The lamps in a string of decorative lights are connected in parallel across a constant - voltage power source. What happens if one lamp burns out? (Assume negligible resistance in the wires leading to the lamps.) The other lamps get brighter equally. The other lamps get dimmer equally. The other lamps get brighter, but some get brighter than others. The brightness of the lamps will not change appreciably. The other lamps get dimmer, but some get dimmer than others.

As I increases the power in each lamp increases, so they all shine more in the same amount

Explanation:

In a parallel circuit the voltage across all the elements is the same, but the current is divided between each element depending on their resistance. If all the lamps are equal, the resistance is divided equally.

Therefore, when a lamp burns out, the circuit of this branch breaks, so the current is divided into equal parts, but in fewer lamps, therefore my current passes through each one.

               I₁ > I₀

The power in each lamp is

          P = V I

          P₁ = V I₁

         P₀ = V I₀

         P₁ > P₀

 As I increases the power in each lamp increases, so they all shine more in the same amount

answer: 31, 5556. 952 seconds

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015