A bat strikes a 0.145 kgkg baseball. Just before impact, the ball is traveling horizontally to the right at 50.0 m/sm/s; when it leaves the bat, the ball is traveling to the left at an angle of 30∘30∘ above horizontal with a speed of 38.0 m/sm/s. The ball and bat are in contact for 1.75 msms. find the horizontal and vertical components of the average force on the ball.

Answer with Explanation:

We are given that

Mass of ball=m=0.145 kg

Initially horizontal  velocity of ball,ux=50 m/s

Final velocity of ball,v=38m/s

Time ,t=1.75 ms=

Horizontal component of average force,

Using the formula

Horizontal component of average force, N

Vertical component of average force,

Vertical component of average force,

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.