In Case 1, a force F is pushing perpendicular on an object a distance L/2 from the rotation axis. In Case 2 the same force is pushing at an angle of 30 degrees a distance L from the axis. 1)In which case is the torque due to the force about the rotation axis biggest?

The answer is c) same.

Explanation:

When a force is applied at some point on a rigid body, the body makes a rotational movement about the axis. Said property of the force applied to rotate the body is calculated with a magnitude known as torque, which is defined as the moment of force at a capacity of that force to make a rotation around a specific point.

for case 1, the magnitude of the torque is equal to:

τ = F*(L/2)

For case 2, the torque magnitude equals:

τ = F*sin(30°) = F*(L/2)

It can be seen that in both cases it is the same torque.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force