The electric field strength E 0 E 0 is measured at a perpendicular distance R R from an infinitely large, thin sheet that contains a uniform positive charge density σ . σ. In terms of the stated properties and the permittivity of free space ε 0 , ε0, write an expression for the electric field strength E E at a perpendicular distance 2 R 2R from the sheet.

same value in R and 2R       E = E₀ = σ / 2ε₀

Explanation:

For this exercise we use Gauss's law

            Ф = E. dA = /ε₀

We define a Gaussian surface with a cylinder with the base being parallel to the load sheet, so the electic field line and the normal line to the base are parallel and the scalar product is reduced to the algebraic product, in the parts the angle is 90º and the dot product is zero

As the sheet has two faces

           2E A = q_{int} /ε₀

The charge inside the cylinder is

           σ = q_{int} / A

           q_{int} = σ A

We substitute

           E = σ / 2ε₀

We see that this expression is independent of the distance, so it has the same value in R and 2R

             E = E₀ = σ / 2ε₀

when the use of electricity burdens the fuse and miniarure circuit beakers and there is a possibility of a fuse then they automatically cut off the electricity supply to your homes and after you fix the problem u jzt switch it on and it continues the supply of electricity to ur homes

battery with hi vtge high val resist in series