A spring hangs from the ceiling with an unstretched length of x 0 = 0.39 m x0=0.39 m . A m 1 = 6.7 kg m1=6.7 kg block is hung from the spring, causing the spring to stretch to a length x 1 = 0.64 m x1=0.64 m . Find the length x 2 x2 of the spring when a m 2 = 3.7 kg m2=3.7 kg block is hung from the spring. For both cases, all vibrations of the spring are allowed to settle down before any measurements are made.

The length is 0.55 meters

Explanation:

When mass m1 is hung from the spring, the spring stretches and we wait until the vibrations are settle down, so in this point the mass is at rest and we can use Newton's first law, this is, the net force on the mass is zero so elastic force (Fk) and weight are equal in magnitude:

weight is mass times gravitational acceleration (g) and elastic force is the length the spring stretches times spring constant (k):

(1)

solving for k and using data provided on 1:

Now knowing k, we can use equation (1) to find x1:

a and c

explanation:

both a and c are correct answers to my knowledge, it's been a bit since i've done anything related to magnetic fields, but it should be right.

15.3 cos 65 degrees trig