A 2.5-cm-diameter parallel-plate capacitor has a 2.2 mm spacing. The electric field strength inside the capacitor is 6.0×104 V/m . You may want to review (Pages 699 - 702) . Part APart complete What is the potential difference across the capacitor? Express your answer to two significant figures and include the appropriate units.

Explanation:

The given data is as follows.

     Separation between two plates, d = 2.2 mm =

     Electric field strength inside the capacitor, E =

Therefore, we will calculate the potential difference across the capacitor as follows.

              V = Ed

                  =

                  = 1.32 V

Thus, we can conclude that the potential difference across the given capacitor is 1.32 V.

k2s for potassium sulphide

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm