A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray in water makes an angle of 36.6° with the normal to the interface, what angle does the ray that is refracted into the glass make with the normal?

θ₂ ≈ 29.7°

Explanation:

Given:

n₁ = 1.33, n₂= 1.60, θ₁ = 36.6°, θ₂ = ?

Solution:

According to snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1.33 × sin (36.6°) = 1.60 × sin θ₂

⇒ Sin θ₂ = 0.496

θ₂ ≈ 29.7°

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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