A mango is dropped from a tree 80m high, with zero initial speed; 1.0s later, another coconut is thrown vertically downward (with non zero initial speed). If both fruits strike the ground at the same time, calculate the initial speed with which the second coconut is thrown.

The initial speed of second coconut us 11.67 m/s

Explanation:

Step 1:

It is given that the first mango is dropped from a tree 80 m high with zero initial velocity. A coconut is then throws after 1 second from the same tree with a non-zero initial speed. We need to calculate the initial speed of the coconut if both the fruits hit the ground simultaneously.

Step 2:

The equation of motion connecting distance traveled, initial velocity and earth's gravity is

For the mango s = 80 m, u =0 , a = 10 we need to find t.

80 = 0 + (1/2) * 10 *

t = 4 seconds.

The mango hits the ground in 4 seconds, so the coconut takes 3 seconds to hit the ground.

Step 3:

For the coconut s = 80 m, t = 3 s, a = 10, we need to find u

80 = u * 3 + (1/2)*10*

u = 35 /3 = 11.67 m/s

Step 4:

The initial speed of second coconut us 11.67 m/s

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

b

explanation: