ASAP URGENT A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1.5 seconds. By how much would the force have been reduced if the car had had a crumple zone that increased the collision time to 2.2 seconds? Give your answer to the nearest whole number in Newtons

8018.2 N

Explanation:

Change in momentum, p is equivalent to force * time

M(vf-vi)=Ft where M represent mass of the car, vf is the final speed, vi is the intial speed of the car, F is the force in queation and t ia the time.

Since the car finally comes to rest then the final velocity ia zero. Substituting 1400 Kg for M, 0 for vf, 27 m/s for vi and 1.5 s for t then the first force is

1400(0-27)=1.5F

F=25200 N

Similarly, when we work with the same values but t changed to 2.2s

1400(0-27)=2.2 F

F2=17181.818181818 N

Reduced force will be 25200-17181.818181818=−8,018.181818182N

Approximately, 8018.2 N

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answer: the correct answer is   air pressure at the top of mount everest is higher than at the bottom of the grand canyon.

hope this : )

explanation: