A heavy ball with a weight of 150 N is hung from the ceiling of a lecture hall on a 4.6-m-long rope. The ball is pulled to one side and released to swing as a pendulum, reaching a speed of 5.1 m/s as it passes through the lowest point. What is the tension in the rope at that point?

236.5 N

Explanation:

The tension in the rope will be given by

where T is the tension on the rope, m is the mass of the ball, v is the speed of the ball of the ball at the lowest point and r is the length of the ball.

Since F=mg then making m the subject, where F is the force and g is acceleration due to gravity. Now replacing m with the above in the dirst equation then

Substituting 150 N for F, 9.81 for g, 5.1 m/s for v and 4.6 m for L then

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

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