How much current must pass through a horizontal power transmission cable in order for the magnetic field at a location 24 mm directly below it to be equal to the Earth's magnetic field, which is approximately 9.0×10−5T9.0×10−5T?

the area between the graph and the t axis

d) physical means can be used to separate the components of air.

i think the answer is a and b

i wish you luck

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m