A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the cord is then connected to a hanging weight. Calculate the force exerted by the ground on the box (in lb), if the hanging weight is 10.5 lb.

The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.

F1 = T- 46, 674.656 gm/s²

Explanation:

Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.

To calculate the force caused by gravity on the basic pulley system we use the following equation:

F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g

∴ F2 = 4762.72g x 9.8 m/s²

= 46, 674.656 gm/s² or 46, 674.656 N

But since this F2 is acting in a downlowrd direction, it would be negative.

Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)

⇒ F1 = T - F2

F1 = T- 46, 674.656 gm/s²

the total distance traveled by the car is

30km + 49km = 79 km .

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