A 0.230-kg block along a horizontal track has a speed of 1.30 m/s immediately before colliding with a light spring of force constant 4.00 N/m located at the end of the track. (a) What is the spring's maximum compression if the track is frictionless?

The maximum compression in the spring is 0.31 meters.

Explanation:

Given that,

Mass of the block, m = 0.23 kg

Speed of the block, v = 1.3 m/s

It collides with the spring of force constant 4 N/m located at the end of the track. We need to find the spring's maximum compression if the track is frictionless. It can be calculated using conservation of energy. The kinetic energy of the block is converted to the potential energy of the spring i.e.

x is the spring's maximum compression

So, the maximum compression in the spring is 0.31 meters. Hence, this is the required solution.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.