A box slides across a frictionless horizontal surface with constant acceleration 3.40 m/s2 and over a time interval reaches a final velocity of 13.0 m/s.

a. If its initial velocity is 6.50 m/s, what is its displacement (in m) during the time interval?

b. What is the distance it travels during this interval?

c. If its initial velocity is -6.00 m/s what is its displacement during the time interval?

d. What is the total distance it travels during the interval in part (c)?

Not what goes around on earth but the universe too.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.