For the material in the previous question that yields at 200 MPa, what is the maximum mass, in kg, that a cylindrical bar with diameter of 4.5 cm can support without yielding ? Recall that a mass of 1 kg has a weight of 9.81 N at sea-level. Answer Format: X (no decimal) Unit: kg Example: of you calculate 41321.78 enter 41322

The maximum mass the bar can support without yielding = 32408.26 kg

Explanation:

Yield stress of the material () = 200 M Pa

Diameter of the bar = 4.5 cm = 45 mm

We know that yield stress of the bar is given by the formula

                Yield Stress =

⇒                                 =  ---------------- (1)

⇒ Area of the bar (A) = ×

⇒                            A  = ×

⇒                            A = 1589.625

Put all the values in equation (1) we get

⇒ = 200 × 1589.625

⇒ = 317925 N

In this bar the is equal to the weight of the bar.

⇒ = × g

Where is the maximum mass the bar can support.

⇒ =

Put all the values in the above formula we get

⇒ =

⇒ = 32408.26 Kg

There fore the maximum mass the bar can support without yielding = 32408.26 kg

found in the nucleus

has mass of one amu

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