The electric field intensity at a particular location surrounding a Van de Graaff generator is 4.5x103 N/C. Determine the magnitude of the force that this field would exert upon ...

The magnitude of the force is

Explanation:

Given that,

Electric field intensity

Suppose, The electron when positioned at this location

We need to calculate the magnitude of the force

Using formula of electric field

Where, E = electric field

q = charge of electron

Put the value into the formula

Hence, The magnitude of the force is

it breaks and dirupture other materials and other sencews from the bottom

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this