How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n?

The number of excess electrons on each sphere is 759

Explanation:

Given that,

distance , d = 20 cm

                    = 0.20 m

let the number of electrons is n  

Electric force (F) = k × (n × e)² /d²

3.33 × = 9 × × (n × 1.602 × )² /0.2²

solving for n

n = 759

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .