Two loudspeakers, 4.5 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.31 m . Assume the speed of sound is 340 m/s. What is the frequency of the sound? If the frequency is then increased while you remain 0.31 m from the center, what is the first frequency for which that location will be a maximum of sound intensity?

f = 16.03 kHz

f = 32.07 kHz

Explanation:

For maximum intensity of sound, the two waves must be in phase.

The phase difference (Δ∅) between two waves is given by

Δ∅ = 2πΔr/λ

λ = 2πΔr/Δ∅

where Δr is given by

Δr = r2 - r1

Δr = √(4.5²+0.31²) - 4.5

Δr = 0.0106 m

λ = 2π*0.00106/Δ∅

For cancellation, the phase difference must be Δ∅ = π

λ = 2π*0.0106/π

λ = 2Δr

λ = 0.0212 m

Finally the frequency can be found using

f = c/λ

f = 340/0.0212

f = 16038 Hz

f = 16.03 kHz

Now if the frequency is then increased while you remain 0.31 m from the center, what is the first frequency for which that location will be a maximum of sound intensity?

The λ will be reduced to half

λ = 2Δr/2

λ = Δr

λ = 0.0106 m

f = c/λ

f = 340/0.0106

f = 32075 Hz

f = 32.07 kHz

the answer is b

explanation:

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.