A charge of -2.720 μC is located at (3.000 m , 4.591 m ), and a charge of 1.600 μC is located at (-2.626 m , 0).There is one point on the line connecting these two charges where the potential is zero. Find this point. There is one point on the line connecting these two charges where the potential is zero. Find this point. Express your answers using three decimal places separated by a comma.

x, y = m please help!

Explanation:

Given that,

Q1=-2.72μC

At the position r1 =(3 , 4.591)m

Q2=1.600 μC

Located at (-2.626 m , 0)

Let the point where the electric potential will be zero be (x, y)

Therefore,

r1=(3-x, 4.952-y)

r2=(-2.626-x, -y)

Then, electric potential at that point is given as

V1+V2=0

Then,

KQ1/r1 +KQ2/r2=0

Divide through by k

Q1/r1+Q2/r2=0

-2.72/(3-x, 4.952-y) + 1.6/(-2.626-x, -y)=0

2.72/(3-x, 4.952-y) =1.6/(-2.626-x, -y)

For x axis

2.72/(3-x)=1.6/(-2.626-x)

Cross multiply

2.72(-2.626-x)=1.6(3-x)

-7.14272-2.72x=4.8-1.6x

-2.72x+1.6x=4.8+7.14272

-1.12x=11.94272

x=-11.94272/1.12

x=-10.663m

For y axis

2.72/(3-x, 4.952-y) =1.6/(-2.626-x, -y)

2.72/(4.952-y)=1.6/-y

Cross multiply

-2.72y=1.6(4.952-y)

-2.72y=7.9232-1.6y

-2.72y+1.6y=7.9232

-1.12y=7.9232

y=7.9232/-1.12

y=-7.074m

(x, y)=(-10.663, -7.074)m

the cellphone, they would then know if the killer would have contacted them or always hated them. or if it was a breakup. but if that is not the case, then it would be the clothing. to put in a bullet, it would have to be put in by hands. hands have finger prints which, would have giving you the answer of who done it.

explanation:

(75°f − 32) × 5/9 = 23.889°c